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5m^2-35m+50=0
a = 5; b = -35; c = +50;
Δ = b2-4ac
Δ = -352-4·5·50
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-15}{2*5}=\frac{20}{10} =2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+15}{2*5}=\frac{50}{10} =5 $
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